<?xml version="1.0" encoding="UTF-8"?><rss version="2.0"
	xmlns:content="http://purl.org/rss/1.0/modules/content/"
	xmlns:dc="http://purl.org/dc/elements/1.1/"
	xmlns:atom="http://www.w3.org/2005/Atom"
	xmlns:sy="http://purl.org/rss/1.0/modules/syndication/"
		>
<channel>
	<title>Comments on: Infinite sums, integer sequences</title>
	<atom:link href="http://nealabq.com/blog/2009/03/19/sums_sequences/feed/" rel="self" type="application/rss+xml" />
	<link>http://nealabq.com/blog/2009/03/19/sums_sequences/</link>
	<description>... dodging grues in the dark</description>
	<lastBuildDate>Tue, 27 Dec 2011 18:28:32 +0000</lastBuildDate>
	<sy:updatePeriod>hourly</sy:updatePeriod>
	<sy:updateFrequency>1</sy:updateFrequency>
	<generator>http://wordpress.org/?v=3.0</generator>
	<item>
		<title>By: CallieZimmerman27</title>
		<link>http://nealabq.com/blog/2009/03/19/sums_sequences/comment-page-1/#comment-133</link>
		<dc:creator>CallieZimmerman27</dc:creator>
		<pubDate>Sat, 14 May 2011 01:37:14 +0000</pubDate>
		<guid isPermaLink="false">http://nealabq.com/blog/?p=1134#comment-133</guid>
		<description>I opine that to get the &lt;a href=&quot;http://bestfinance-blog.com&quot; rel=&quot;nofollow&quot;&gt;loan&lt;/a&gt; from creditors you ought to have a good reason. However, one time I&#039;ve received a bank loan, just because I wanted to buy a bike.</description>
		<content:encoded><![CDATA[<p>I opine that to get the <a href="http://bestfinance-blog.com" rel="nofollow">loan</a> from creditors you ought to have a good reason. However, one time I&#8217;ve received a bank loan, just because I wanted to buy a bike.</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: Peter Luthy</title>
		<link>http://nealabq.com/blog/2009/03/19/sums_sequences/comment-page-1/#comment-80</link>
		<dc:creator>Peter Luthy</dc:creator>
		<pubDate>Sat, 18 Apr 2009 08:00:14 +0000</pubDate>
		<guid isPermaLink="false">http://nealabq.com/blog/?p=1134#comment-80</guid>
		<description>Hi Neal,

Thanks very much for your kind words, and I&#039;m glad that you found the information on my post interesting.  I read your page and am happy to hear that you are teaching your son mathematics and experimental mathematics.  The confidence that one can discover things on one&#039;s own is a fantastic gift to give to a child.

Peter</description>
		<content:encoded><![CDATA[<p>Hi Neal,</p>
<p>Thanks very much for your kind words, and I&#8217;m glad that you found the information on my post interesting.  I read your page and am happy to hear that you are teaching your son mathematics and experimental mathematics.  The confidence that one can discover things on one&#8217;s own is a fantastic gift to give to a child.</p>
<p>Peter</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: Neal</title>
		<link>http://nealabq.com/blog/2009/03/19/sums_sequences/comment-page-1/#comment-79</link>
		<dc:creator>Neal</dc:creator>
		<pubDate>Fri, 17 Apr 2009 17:34:42 +0000</pubDate>
		<guid isPermaLink="false">http://nealabq.com/blog/?p=1134#comment-79</guid>
		<description>Related post:
http://cornellmath.wordpress.com/2009/04/05/a-sill-infinite-series/</description>
		<content:encoded><![CDATA[<p>Related post:<br />
<a href="http://cornellmath.wordpress.com/2009/04/05/a-sill-infinite-series/" rel="nofollow">http://cornellmath.wordpress.com/2009/04/05/a-sill-infinite-series/</a></p>
]]></content:encoded>
	</item>
	<item>
		<title>By: Neal</title>
		<link>http://nealabq.com/blog/2009/03/19/sums_sequences/comment-page-1/#comment-72</link>
		<dc:creator>Neal</dc:creator>
		<pubDate>Wed, 25 Mar 2009 18:24:01 +0000</pubDate>
		<guid isPermaLink="false">http://nealabq.com/blog/?p=1134#comment-72</guid>
		<description>Thanks Zealot. I&#039;d never get that on my own. I guess you&#039;ve also proven that sum((n^2)/(B^n)) is (B(B+1))/((B-1)^3). You just have to plug in B wherever there&#039;s a 10.

Anyway, I&#039;ll show it to my son. It&#039;ll be a good excuse to introduce him to differentials.</description>
		<content:encoded><![CDATA[<p>Thanks Zealot. I&#8217;d never get that on my own. I guess you&#8217;ve also proven that sum((n^2)/(B^n)) is (B(B+1))/((B-1)^3). You just have to plug in B wherever there&#8217;s a 10.</p>
<p>Anyway, I&#8217;ll show it to my son. It&#8217;ll be a good excuse to introduce him to differentials.</p>
]]></content:encoded>
	</item>
</channel>
</rss>

